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Lady Justice illustration, Lady Justice Themis, others, white, police Officer, hand png 834x1500px 99.11KB.Lady Justice Symbol Themis Lawyer, symbol, white, hand, libra png 518x962px 140.64KB.Lady Justice Symbol Measuring Scales Law, symbol, libra, measuring Scales, sign png 800圆47px 24.04KB.Quadratics can of course be solved by using the familiar quadratic formula, but it is often easier to use an algebraic or graphical approximation, and for higher-order equations this is the only practical approach.
This very often involves solving a quadratic or higher-order equation. You then substitute the equilibrium values into the equilibrium constant expression, and solve it for the unknown. The easiest and most error-free way of doing this is adopt a systematic approach in which you create and fill in a small table as shown in the following problem example. The key to this is to make use of the stoichiometric relationships between the various components, which usually allow us to express the equilibrium composition in terms of a single variable. This is by far the most common kind of equilibrium problem you will encounter: starting with an arbitrary number of moles of each component, how many moles of each will be present when the system comes to equilibrium? The principal source of confusion and error for beginners relates to the need to determine the values of several unknowns (a concentration or pressure for each component) from a single equation, the equilibrium expression. Substituting into the equilibrium expression above gives \(K_p = 1.2\). \) that remains and its fractional dissociation is (1 – 0.76) = 0.24.
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